Project1

标题: 脚本问题 [打印本页]

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作者: ae3175001    时间: 2013-10-2 23:07
标题: 脚本问题
0.1 <= a <= 0.5
如何用脚本表达a在0.1到0.5之间，最小时为0.1最大时为0.5 ，求简洁的脚本代码

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作者: 喵呜喵5    时间: 2013-10-2 23:27
a.between?(0.1,0.5)
(0.1..0.5)===a
(0.1..0.5).member?a
(0.1..0.5).include?a

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作者: xTsukihime    时间: 2013-10-3 01:35


我建議

1. 0.1 <= a && a <= 0.5

复制代码

意思是 ”0.1<= a和 a <= 0.5“
而且比別的快2-4倍

1. require 'Benchmark'
   
2. a = 0.2
   
3. n = 100000
   
4. 
   
5. Benchmark.bm {|x|
   
6.   x.report { n.times{a.between?(0.1,0.5)}}
   
7.   x.report { n.times{(0.1..0.5)===a}}
   
8.   x.report { n.times{(0.1..0.5).member?a}}
   
9.   x.report { n.times{(0.1..0.5).include?a}}
   
10.   x.report { n.times{ 0.1 <= a && a <= 0.5}}
    
11. }

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1.        user     system      total        real
   
2.    0.047000   0.000000   0.047000 (  0.034002)
   
3.    0.078000   0.000000   0.078000 (  0.088005)
   
4.    0.078000   0.000000   0.078000 (  0.081004)
   
5.    0.093000   0.000000   0.093000 (  0.081005)
   
6.    0.016000   0.000000   0.016000 (  0.025001)

复制代码

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作者: tan12345    时间: 2013-10-3 10:14
如果是取值范围，a=(rand(5)+1)/10
如果是判断，if a>=0.1 and a<=0.5

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