请教大家如何用一句话判断队里是否有人装备了第100号防具

taeckle

目前咱能用两句话判断这个条件，两句话判断这么写：
for i in 1..999 #反正最多就999个角色.. (这是第一句)
if $game_party.actors.include?($game_actors[i])  && $game_actors[i].armor1_id == 100    #(这是第二句)
return true
break
end
end

那要是只用1句话该怎么判断呢？
还请大神指点一二，多谢了！

orochi2k

1. def Greetings_Ladies_And_Gentlemen_Would_You_Kindly_Tell_Me_If_Any_of_You_Equiped_An_Amrmor_Whose(id = 100);for actor in $game_party.actors;if actor.armor1_id == id or actor.armor2_id == id or actor.armor3_id == id or actor.armor4_id == id; return true;end;end;return false;end; Greetings_Ladies_And_Gentlemen_Would_You_Kindly_Tell_Me_If_Any_of_You_Equiped_An_Amrmor_Whose(100)

复制代码

论如何优雅地向队伍中的成员发问(大雾)
对,我是故意来捣乱的.(大雾)
不过你会发现丢到事件的条件分歧里放这么一段真的可以跑

YukiYukidesu

1. $game_party.actors.any? {|i| [i.armor1_id, i.armor2_id, i.armor3_id, i.armor4_id].include?(100) }

复制代码

soulsaga

RUBY 代码复制

$game_party.actors.size.times {|i| return true if $game_party.actors[i].armor1_id==100 }

$game_party.actors.size.times {|i| return true if $game_party.actors[i].armor1_id==100 }