怎么用API修改程序图标 - Project1

#修改程序ico方法
file_name = "Graphics/Pictures/ico32.ico"
@get_ico = Win32API.new("user32", "LoadCursorFromFile", 'l', 'l')
@sendmessage = Win32API.new("user32", "SendMessage", 'lllp', 'l')
icon = @get_ico.call() #这里不知道怎么写啊
@sendmessage.call(get_hWnd, 0x0080, nil, icon)

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# ■ Kernel
#------------------------------------------------------------------------------
# 　该模块中定义了可供所有类使用的方法。Object 类中包含了该模块。
#==============================================================================
module Kernel
#--------------------------------------------------------------------------
# ● 需要的 Windows API 函数
#--------------------------------------------------------------------------
GetWindowThreadProcessId = Win32API.new("user32", "GetWindowThreadProcessId", "LP", "L")
GetWindow = Win32API.new("user32", "GetWindow", "LL", "L")
GetClassName = Win32API.new("user32", "GetClassName", "LPL", "L")
GetCurrentThreadId = Win32API.new("kernel32", "GetCurrentThreadId", "V", "L")
GetForegroundWindow = Win32API.new("user32", "GetForegroundWindow", "V", "L")
#--------------------------------------------------------------------------
# ● 获取窗口句柄
#--------------------------------------------------------------------------
def get_hWnd
# 获取调用线程（RM 的主线程）的进程标识
threadID = GetCurrentThreadId.call
# 获取 Z 次序中最靠前的窗口
hWnd = GetWindow.call(GetForegroundWindow.call, 0)
# 枚举所有窗口
while hWnd != 0
# 如果创建该窗口的线程标识匹配本线程标识
if threadID == GetWindowThreadProcessId.call(hWnd, 0)
# 分配一个 11 个字节的缓冲区
className = " " * 11
# 获取该窗口的类名
GetClassName.call(hWnd, className, 12)
# 如果匹配 RGSS Player 则跳出循环
break if className == "RGSS Player"
end
# 获取下一个窗口
hWnd = GetWindow.call(hWnd, 2)
end
return hWnd
end
end

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file_name = "Graphics/Pictures/ico32.ico"
@get_ico = Win32API.new("user32", "LoadCursorFromFile", 'p', 'l')
@sendmessage = Win32API.new("user32", "SendMessage", 'lllp', 'l')
icon = @get_ico.call(file_name)
@sendmessage.call(get_hWnd, 0x0080, 0, icon)

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