Project1
标题:
队伍角色位置整理
[打印本页]
作者:
ahoucbvtw
时间:
2017-2-14 23:16
标题:
队伍角色位置整理
由于我在游戏上会设定原先角色离队然后再次将他加入
但是目前遇到一个问题就是每次我这样离队又入队就会换一个角色行走
我想要随时指定那位离开的角色为队伍的第一人(也就是行走时都是使用他)
能否给个方向?脚本也行?
拜托
作者:
yang1zhi
时间:
2017-2-15 13:01
https://rpg.blue/forum.php?mod=viewthread&tid=80913
作者:
1095884734
时间:
2017-3-5 09:49
本帖最后由 1095884734 于 2017-3-5 09:50 编辑
def 队伍还原
if $game_switches[20] == true
if $game_variables[2] == 0
$game_party.remove_actor(2)
$game_party.add_actor(2)
else
$game_party.remove_actor(9+$game_variables[2])
$game_party.add_actor(9+$game_variables[2])
end
end
if $game_switches[21] == true
if $game_variables[3] == 0
$game_party.remove_actor(3)
$game_party.add_actor(3)
else
$game_party.remove_actor(9+$game_variables[3])
$game_party.add_actor(9+$game_variables[3])
end
end
if $game_switches[22] == true
if $game_variables[50] == 0
$game_party.remove_actor(4)
$game_party.add_actor(4)
else
$game_party.remove_actor(9+$game_variables[50])
$game_party.add_actor(9+$game_variables[50])
end
end
if $game_variables[4] == 0
else
$game_party.remove_actor(9+$game_variables[4])
$game_party.add_actor(9+$game_variables[4])
end
end
def 队伍还原二
if $game_switches[21] == true
if $game_variables[3] == 0
$game_party.remove_actor(3)
$game_party.add_actor(3)
else
$game_party.remove_actor(9+$game_variables[3])
$game_party.add_actor(9+$game_variables[3])
end
end
if $game_switches[22] == true
if $game_variables[50] == 0
$game_party.remove_actor(4)
$game_party.add_actor(4)
else
$game_party.remove_actor(9+$game_variables[50])
$game_party.add_actor(9+$game_variables[50])
end
end
if $game_variables[4] == 0
else
$game_party.remove_actor(9+$game_variables[4])
$game_party.add_actor(9+$game_variables[4])
end
end
def 队伍还原三
if $game_switches[22] == true
if $game_variables[50] == 0
$game_party.remove_actor(4)
$game_party.add_actor(4)
else
$game_party.remove_actor(9+$game_variables[50])
$game_party.add_actor(9+$game_variables[50])
end
end
if $game_variables[4] == 0
else
$game_party.remove_actor(9+$game_variables[4])
$game_party.add_actor(9+$game_variables[4])
end
end
def 队伍还原四
=begin
unless $game_variables[4] == 0
$game_party.remove_actor(4+$game_variables[4])
$game_party.add_actor(4+$game_variables[4])
end
=end
end
复制代码
或者说用公共事件
用开关判定队友的人数
然后队友加入、离开来调整顺序
作者:
guoxiaomi
时间:
2017-3-5 12:34
单纯的让队伍里的角色按照ID来排序的方法:
$game_party.actors.sort!{|a| a.id}
$game_player.refresh
复制代码
把这个用事件脚本插在“加入队伍”指令的后面。这样只要保证新加入的角色的ID比较小,就会显示这个角色的行走图。
作者:
cinderelmini
时间:
2017-3-5 15:10
如果队伍成员排序一直是固定的话,其实用事件就可以了,
比如一开始队伍成员:【1,2,3,4】,
1离队了,队伍剩下【2,3,4】,
然后1回来了,队伍变成【2,3,4,1】,
这时候,让队伍里的2,3,4逐一离队,队伍就变成了【1】了,
然后再把2,3,4加入队伍,那么队伍就变回原来的样子了。
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