【已解决】显示10张图片任意消失2张剩下的8张图片间隔x87...

金芒芒

一共显示10张图片，其中消失任意2张图片剩下的8张按图片编号顺序每张x数值间隔87

RUBY 代码复制

x=0
for i in 1...10
$game_screen.pictures[i].show("头像#{i}", 0, 
x, 160, 100, 100, 255, 0)
 
x+=87
 
end

x=0


for i in 1...10


$game_screen.pictures[i].show("头像#{i}", 0, 


x, 160, 100, 100, 255, 0)


 


x+=87


 


end

链接: https://pan.baidu.com/s/1BWoXmsXCJslTp21bxRNYIQ?pwd=9j7x 提取码: 9j7x

soulsaga

RUBY 代码复制

a=[1,2,3,4,5,6,7,8,9,10]
x=0
a.delete(5)
a.delete(3)
for i in a
$game_screen.pictures[i].show("头像#{i}", 0, 
x, 160, 100, 100, 255, 0)
x+=87
end

a=[1,2,3,4,5,6,7,8,9,10]


x=0


a.delete(5)


a.delete(3)


for i in a


$game_screen.pictures[i].show("头像#{i}", 0, 


x, 160, 100, 100, 255, 0)


x+=87


end

金芒芒

soulsaga 发表于 2023-7-3 13:50
a=[1,2,3,4,5,6,7,8,9,10]
x=0
a.delete(5)

可以了问了你2个星期大功告成了，太感谢你了

金芒芒

soulsaga 发表于 2023-7-3 13:50
a=[1,2,3,4,5,6,7,8,9,10]
x=0
a.delete(5)

效果很完美