这段脚本能否放进事件脚本框里?

stella

有点长,如何压缩?

RUBY 代码复制

b=($game_party.actors[
0].hp).to_f/($game_party.actors[0].maxhp).to_f
a=[];for i in 11..14
name = $game_map.events[i].name
data=name.split(/,/)
if data[1].to_i <= 0;a[i]=2
else;a[i]=data[1].to_f/data[2].to_f;end
end;for i in 1..10
next if $game_self_switches[[
$game_map.map_id,i,"D"]]==true or
$game_map.events[i].character_name == ""
if a.min==1 or a.min>b;$friend14_target=0
elsif a.min == a[i];$friend14_target = i
end;end

b=($game_party.actors[


0].hp).to_f/($game_party.actors[0].maxhp).to_f


a=[];for i in 11..14


name = $game_map.events[i].name


data=name.split(/,/)


if data[1].to_i <= 0;a[i]=2


else;a[i]=data[1].to_f/data[2].to_f;end


end;for i in 1..10


next if $game_self_switches[[


$game_map.map_id,i,"D"]]==true or


$game_map.events[i].character_name == ""


if a.min==1 or a.min>b;$friend14_target=0


elsif a.min == a[i];$friend14_target = i


end;end

zhangbanxian

上面加个def xxx，下面加个end，丢脚本编辑器里，然后事件里就输入xxx就行了- -b

亿万星辰

1. c=$game_party.actors[0]
   
2. b=c.hp*1.0/c.maxhp;a=[];for i in 11..14
   
3. data=$game_map.events[i].name.split(/,/)
   
4. if data[1].to_i <= 0;a[i]=2;else
   
5. a[i]=data[1].to_f/data[2].to_f;end;end
   
6. for i in 1..10;
   
7. next if $game_self_switches[[\
   
8. $game_map.map_id,i,"D"]]==true or\
   
9. $game_map.events[i].character_name == ""
   
10. if a.min==1 or a.min>b;$friend14_target=0
    
11. elsif a.min == a[i];$friend14_target = i
    
12. end;end

复制代码

hys111111

亿万星辰 发表于 2013-1-8 11:47

大概可以分开放进去的吧，像这个样子。