求用脚本表示事件的前面一格的地形标志的方法

Wind2010

不能用事件……因为我用的条件判断是脚本……

zhangbanxian

orz我想不出地形标志除了用于判断还有啥用途...代入1号变量得了- -b

1. if $game_map.events[事件id].direction == 6
   
2. x = $game_map.terrain_tag($game_map.events[事件id].x+1
   
3. y = $game_map.events[事件id].y)
   
4. elseif $game_map.events[事件id].direction == 4
   
5. x = $game_map.events[事件id].x-1
   
6. y = $game_map.events[事件id].y
   
7. elseif $game_map.events[事件id].direction == 2
   
8. x = $game_map.events[事件id].x
   
9. y = $game_map.events[事件id].y+1
   
10. elseif $game_map.events[事件id].direction == 8
    
11. x = $game_map.events[事件id].x
    
12. y = $game_map.events[事件id].y-1
    
13. end
    
14. $game_variables[1] = $game_map.terrain_tag(x,y)

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PS:脚本越长越好- -b

fux4

手机写的，不知道有没有错误

1. a = $game_map.events[1].direction
   
2. b = $game_map.events[1].x
   
3. c = $game_map.events[1].y
   
4. d = (a == 4 or a == 6 ? (b+5-a).to_i : b)
   
5. e = (a == 2 or a == 8 ? (c+(5-a)/2).to_i : c)
   
6. p $game_map.terrain_tag(d,e)

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逸豫

1. class Interpreter
   
2.   def event_face_tag(event)
   
3.     x = event.x
   
4.     y = event.y
   
5.     d = event.direction
   
6.     new_x = x + (d == 6 ? 1 : d == 4 ? -1 : 0)
   
7.     new_y = y + (d == 2 ? 1 : d == 8 ? -1 : 0)
   
8.     return $game_map.terrain_tag(new_x, new_y)
   
9.   end
   
10. end

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扔到脚本编辑器里
事件里这样写：
a = $game_map.events[事件ID]
p event_face_tag(a)