求助，怎么让这个事件变成另的时候的时候ID不变

yang1zhi

$game_map.events[$game_system.friend_event_id[0]] 这个事件会变成BFS_Friends.get_event_to(id, temp.x, temp.y))这个事件。
但是我希望他的ID不变

RUBY 代码复制

def exchange_event
    id = @actors[@actors.size - 1].id
    temp = $game_map.events[$game_system.friend_event_id[0]]
    $game_map.events[$game_system.friend_event_id[0]] = \
    Game_Friend.new($game_system.friend_event_id[0], \
    BFS_Friends.get_event_to(id, temp.x, temp.y))
  end

def exchange_event


    id = @actors[@actors.size - 1].id


    temp = $game_map.events[$game_system.friend_event_id[0]]


    $game_map.events[$game_system.friend_event_id[0]] = \


    Game_Friend.new($game_system.friend_event_id[0], \


    BFS_Friends.get_event_to(id, temp.x, temp.y))


  end