能力曲线是否能做成这种形式(中间加颜色)?500分

闪电 · 发表于 2008-10-19 01:04:22

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原图:

能力曲线改造后,曲线包围的范围加了颜色:

原脚本:

#---------------------------------------------------
# 本脚本来自66RPG.com，作者Deathless
#---------------------------------------------------
#-----------------------------------------------------
# 功能设定
# 当＝1和＝2，会改变图形的大小
# ＝1的时候，图形为每个人自身的能力分配，最大数就是顶点
# ＝2的时候，图形为所有人的能力分配，顶点为999
#
# 如果不需要999这么大，本脚本中搜索
# "c[i] = get_position(a[0][0], a[0][1], a[i+1][0], a[i+1][1], b[i] / 999.0)"
# 把这个999修改了即可。
#-----------------------------------------------------
ST_DRAW_SIX_LINES_TYPE = 2
class Bitmap
#--------------------------------------------------------------------------
# ● 描绘直线
# x1，y1，x2，y2：直线两端的坐标
# width：宽度
# color：颜色
#--------------------------------------------------------------------------
def drawline(x1, y1, x2, y2, width, color)
x1 = x1.to_f
y1 = y1.to_f
x2 = x2.to_f
y2 = y2.to_f
width = width.to_f
k = (y2 - y1) / (x2 - x1)
if k.abs > 1
drawline_x(x1, y1, x2, y2, width, color)
else
drawline_y(x1, y1, x2, y2, width, color)
end
end
def drawline_x(x1, y1, x2, y2, width, color)
l = ((x1 - x2) ** 2 + (y1 - y2) ** 2) ** 0.5 * width / (y1 - y2)
length = l.abs * 2
k = (x2 - x1) / (y2 - y1) #x=ky+b
b = x1 - k * y1
if l > 0
for ty in y2.to_i..y1.to_i
tx = ty * k + b
fill_rect(tx - l, ty, length, 1, color)
end
else
for ty in y1.to_i..y2.to_i
tx = ty * k + b
fill_rect(tx + l, ty, length, 1, color)
end
end
end
def drawline_y(x1, y1, x2, y2, width, color)
l = ((x1 - x2) ** 2 + (y1 - y2) ** 2) ** 0.5 * width / (x1 - x2)
height = l.abs * 2
k = (y2 - y1) / (x2 - x1) #y=kx+b
b = y1 - k * x1
if l > 0
for tx in x2.to_i..x1.to_i
ty = tx * k + b
fill_rect(tx, ty - l, 1, height, color)
end
else
for tx in x1.to_i..x2.to_i
ty = tx * k + b
fill_rect(tx, ty + l, 1, height, color)
end
end
end
end
class Window_Status < Window_Base
def get_position(x_begin, y_begin, x_end, y_end, percent)
a = []
a[0] = x_begin + (x_end - x_begin) * percent
a[1] = y_begin + (y_end - y_begin) * percent
return a
end
def refresh
self.contents.clear
x0 = 60 #图表的坐标
y0 = 220
r = 100.0 #图表的大小，友情提示：浮点数后面的.0不要省略了
h = 3 ** 0.5 * r / 2
a = [] #六边形的顶点和圆心
a[0] = [r, h] #圆心
a[1] = [r / 2, 0.0]
a[2] = [r * 3 / 2, 0.0]
a[6] = [0.0, h]
a[3] = [r * 2, h]
a[5] = [r / 2, h * 2]
a[4] = [r * 3 / 2, h * 2]
for i in a
i[0] += x0
i[1] += y0
end
self.contents.font.color = system_color
self.contents.draw_text(a[1][0] - 16 , a[1][1] - 32, 80, 32, "攻")
self.contents.draw_text(a[2][0] - 4, a[2][1] - 32, 80, 32, "防")
self.contents.draw_text(a[6][0] - 28, a[6][1] - 16, 80, 32, "力")
self.contents.draw_text(a[5][0] - 16, a[5][1], 80, 32, "敏")
self.contents.draw_text(a[4][0] - 4, a[4][1], 80, 32, "速")
self.contents.draw_text(a[3][0] + 8, a[3][1] - 16, 80, 32, "魔")
#描绘边框
for i in 1...a.size
self.contents.drawline(a[0][0], a[0][1], a[i][0], a[i][1], 1, disabled_color)
end
self.contents.drawline(a[1][0], a[1][1], a[2][0], a[2][1], 1, text_color(6))
self.contents.drawline(a[2][0], a[2][1], a[3][0], a[3][1], 1, text_color(6))
self.contents.drawline(a[3][0], a[3][1], a[4][0], a[4][1], 1, text_color(6))
self.contents.drawline(a[4][0], a[4][1], a[5][0], a[5][1], 1, text_color(6))
self.contents.drawline(a[5][0], a[5][1], a[6][0], a[6][1], 1, text_color(6))
self.contents.drawline(a[6][0], a[6][1], a[1][0], a[1][1], 1, text_color(6))
#描绘能力曲线
b = [] #获取能力值
b.push(@actor.atk)
b.push(@actor.pdef)
b.push(@actor.int)
b.push(@actor.agi)
b.push(@actor.dex)
b.push(@actor.str)
case ST_DRAW_SIX_LINES_TYPE
when 2
#跟999作比较
c = []
for i in 0...b.size
c[i] = get_position(a[0][0], a[0][1], a[i+1][0], a[i+1][1], b[i] / 999.0)
end
for i in 0...c.size
self.contents.drawline(c[i][0], c[i][1], c[i-1][0], c[i-1][1], 1, text_color(3))
end
when 1
#跟最高能力值比较
max_abi = 0
b.each{|i| max_abi = [max_abi, i].max}
max_abi = max_abi.to_f
c = [] #获得能力值的坐标
for i in 0...b.size
c[i] = get_position(a[0][0], a[0][1], a[i+1][0], a[i+1][1], b[i] / max_abi)
end
for i in 0...c.size
self.contents.drawline(c[i][0], c[i][1], c[i-1][0], c[i-1][1], 1, text_color(3))
end
end
#描绘能力数值
self.contents.font.color = knockout_color
self.contents.font.size = 14
for i in 0...b.size
self.contents.draw_text(c[i][0], c[i][1], 32, 24, b[i].to_s)
end
self.contents.font.size = 22
#以下未修改
draw_actor_graphic(@actor, 40, 112)
draw_actor_name(@actor, 4, 0)
draw_actor_class(@actor, 4 + 144, 0)
draw_actor_level(@actor, 96, 32)
draw_actor_state(@actor, 96, 64)
draw_actor_hp(@actor, 96, 112, 172)
draw_actor_sp(@actor, 96, 144, 172)
self.contents.font.color = system_color
self.contents.draw_text(320, 48, 80, 32, "EXP")
self.contents.draw_text(320, 80, 80, 32, "NEXT")
self.contents.font.color = normal_color
self.contents.draw_text(320 + 80, 48, 84, 32, @actor.exp_s, 2)
self.contents.draw_text(320 + 80, 80, 84, 32, @actor.next_rest_exp_s, 2)
self.contents.font.color = system_color
self.contents.draw_text(320, 160, 96, 32, "装备")
draw_item_name($data_weapons[@actor.weapon_id], 320 + 16, 208)
draw_item_name($data_armors[@actor.armor1_id], 320 + 16, 256)
draw_item_name($data_armors[@actor.armor2_id], 320 + 16, 304)
draw_item_name($data_armors[@actor.armor3_id], 320 + 16, 352)
draw_item_name($data_armors[@actor.armor4_id], 320 + 16, 400)
end
end

复制代码

此贴于 2008-10-20 11:46:42 被版主darkten提醒，请楼主看到后对本贴做出回应。

dbshy · 发表于 2008-10-19 04:20:14

其实就是填充三角形 = =
填充六个以中心和c[0],c[1] c[i-1][0],c[i-1][1] 两点的三角形

for i in 0...c.size
self.contents.drawline(c[0], c[1], c[i-1][0], c[i-1][1], 1, text_color(3))
end
画线的同时画三角形即可

PS:关于三角形的脚本去搜一下,我记得有很多,就是不知道效率如何 = =

替天行乐 · 发表于 2008-10-19 04:40:57

提示: 作者被禁止或删除内容自动屏蔽

闪电 · 发表于 2008-10-21 07:02:51

脚本比较脑残,具体填充法不明确,继续顶一下

dbshy · 发表于 2008-10-21 17:08:19

刚才我试一下，可以实现你要的效果，但就是太卡，果然填充是个大问题 = =

等待高手给出更有效率的填充

闪电 · 发表于 2008-10-22 05:48:48

再顶下吧~~~~~~

redant · 发表于 2008-10-23 17:24:06

#---------------------------------------------------
# 本脚本来自66RPG.com，作者Deathless
#---------------------------------------------------
#-----------------------------------------------------
# 功能设定
# 当＝1和＝2，会改变图形的大小
# ＝1的时候，图形为每个人自身的能力分配，最大数就是顶点
# ＝2的时候，图形为所有人的能力分配，顶点为999
#
# 如果不需要999这么大，本脚本中搜索
# "c[i] = get_position(a[0][0], a[0][1], a[i+1][0], a[i+1][1], b[i] / 999.0)"
# 把这个999修改了即可。
#-----------------------------------------------------
ST_DRAW_SIX_LINES_TYPE = 2
class Bitmap
#--------------------------------------------------------------------------
# ● 描绘直线
# x1，y1，x2，y2：直线两端的坐标
# width：宽度
# color：颜色
#--------------------------------------------------------------------------
def drawline(x1, y1, x2, y2, width, color)
x1 = x1.to_f
y1 = y1.to_f
x2 = x2.to_f
y2 = y2.to_f
width = width.to_f
k = (y2 - y1) / (x2 - x1)
if k.abs > 1
drawline_x(x1, y1, x2, y2, width, color)
else
drawline_y(x1, y1, x2, y2, width, color)
end
end
def drawline_x(x1, y1, x2, y2, width, color)
l = ((x1 - x2) ** 2 + (y1 - y2) ** 2) ** 0.5 * width / (y1 - y2)
length = l.abs * 2
k = (x2 - x1) / (y2 - y1) #x=ky+b
b = x1 - k * y1
if l > 0
for ty in y2.to_i..y1.to_i
tx = ty * k + b
fill_rect(tx - l, ty, length, 1, color)
end
else
for ty in y1.to_i..y2.to_i
tx = ty * k + b
fill_rect(tx + l, ty, length, 1, color)
end
end
end
def drawline_y(x1, y1, x2, y2, width, color)
l = ((x1 - x2) ** 2 + (y1 - y2) ** 2) ** 0.5 * width / (x1 - x2)
height = l.abs * 2
k = (y2 - y1) / (x2 - x1) #y=kx+b
b = y1 - k * x1
if l > 0
for tx in x2.to_i..x1.to_i
ty = tx * k + b
fill_rect(tx, ty - l, 1, height, color)
end
else
for tx in x1.to_i..x2.to_i
ty = tx * k + b
fill_rect(tx, ty + l, 1, height, color)
end
end
end
end
class Window_Status < Window_Base
def get_position(x_begin, y_begin, x_end, y_end, percent)
a = []
a[0] = x_begin + (x_end - x_begin) * percent
a[1] = y_begin + (y_end - y_begin) * percent
return a
end
def refresh
self.contents.clear
x0 = 60 #图表的坐标
y0 = 220
r = 100.0 #图表的大小，友情提示：浮点数后面的.0不要省略了
h = 3 ** 0.5 * r / 2
a = [] #六边形的顶点和圆心
a[0] = [r, h] #圆心
a[1] = [r / 2, 0.0]
a[2] = [r * 3 / 2, 0.0]
a[6] = [0.0, h]
a[3] = [r * 2, h]
a[5] = [r / 2, h * 2]
a[4] = [r * 3 / 2, h * 2]
for i in a
i[0] += x0
i[1] += y0
end
self.contents.font.color = system_color
self.contents.draw_text(a[1][0] - 16 , a[1][1] - 32, 80, 32, "攻")
self.contents.draw_text(a[2][0] - 4, a[2][1] - 32, 80, 32, "防")
self.contents.draw_text(a[6][0] - 28, a[6][1] - 16, 80, 32, "力")
self.contents.draw_text(a[5][0] - 16, a[5][1], 80, 32, "敏")
self.contents.draw_text(a[4][0] - 4, a[4][1], 80, 32, "速")
self.contents.draw_text(a[3][0] + 8, a[3][1] - 16, 80, 32, "魔")
#画矩形
for p in 0...100
p += 1
self.contents.drawline(a[1][0]+p, a[1][1], a[5][0]+p, a[5][1], 2, text_color(1))
end
#画 4个三角形
for i in 0...50
i += 1
self.contents.drawline(a[6][0]+i, a[6][1], a[1][0],a[1][1] , 1, text_color(1))
self.contents.drawline(a[6][0]+i, a[6][1], a[5][0],a[5][1] , 1, text_color(1))
self.contents.drawline(a[3][0]-i, a[6][1], a[2][0],a[2][1] , 1, text_color(1))
self.contents.drawline(a[3][0]-i, a[6][1], a[4][0],a[4][1] , 1, text_color(1))
end
#描绘边框
for i in 1...a.size
self.contents.drawline(a[0][0], a[0][1], a[i][0], a[i][1], 1, disabled_color)
end
self.contents.drawline(a[1][0], a[1][1], a[2][0], a[2][1], 1, text_color(6))
self.contents.drawline(a[2][0], a[2][1], a[3][0], a[3][1], 1, text_color(6))
self.contents.drawline(a[3][0], a[3][1], a[4][0], a[4][1], 1, text_color(6))
self.contents.drawline(a[4][0], a[4][1], a[5][0], a[5][1], 1, text_color(6))
self.contents.drawline(a[5][0], a[5][1], a[6][0], a[6][1], 1, text_color(6))
self.contents.drawline(a[6][0], a[6][1], a[1][0], a[1][1], 1, text_color(6))
#描绘能力曲线
b = [] #获取能力值
b.push(@actor.atk)
b.push(@actor.pdef)
b.push(@actor.int)
b.push(@actor.agi)
b.push(@actor.dex)
b.push(@actor.str)
case ST_DRAW_SIX_LINES_TYPE
when 2
#跟999作比较
c = []
for i in 0...b.size
c[i] = get_position(a[0][0], a[0][1], a[i+1][0], a[i+1][1], b[i] / 999.0)
end
for i in 0...c.size
self.contents.drawline(c[i][0], c[i][1], c[i-1][0], c[i-1][1], 1, text_color(3))
end
when 1
#跟最高能力值比较
max_abi = 0
b.each{|i| max_abi = [max_abi, i].max}
max_abi = max_abi.to_f
c = [] #获得能力值的坐标
for i in 0...b.size
c[i] = get_position(a[0][0], a[0][1], a[i+1][0], a[i+1][1], b[i] / max_abi)
end
for i in 0...c.size
self.contents.drawline(c[i][0], c[i][1], c[i-1][0], c[i-1][1], 1, text_color(3))
end
end
#描绘能力数值
self.contents.font.color = knockout_color
self.contents.font.size = 14
for i in 0...b.size
self.contents.draw_text(c[i][0], c[i][1], 32, 24, b[i].to_s)
end
self.contents.font.size = 22
#以下未修改
draw_actor_graphic(@actor, 40, 112)
draw_actor_name(@actor, 4, 0)
draw_actor_class(@actor, 4 + 144, 0)
draw_actor_level(@actor, 96, 32)
draw_actor_state(@actor, 96, 64)
draw_actor_hp(@actor, 96, 112, 172)
draw_actor_sp(@actor, 96, 144, 172)
self.contents.font.color = system_color
self.contents.draw_text(320, 48, 80, 32, "EXP")
self.contents.draw_text(320, 80, 80, 32, "NEXT")
self.contents.font.color = normal_color
self.contents.draw_text(320 + 80, 48, 84, 32, @actor.exp_s, 2)
self.contents.draw_text(320 + 80, 80, 84, 32, @actor.next_rest_exp_s, 2)
self.contents.font.color = system_color
self.contents.draw_text(320, 160, 96, 32, "装备")
draw_item_name($data_weapons[@actor.weapon_id], 320 + 16, 208)
draw_item_name($data_armors[@actor.armor1_id], 320 + 16, 256)
draw_item_name($data_armors[@actor.armor2_id], 320 + 16, 304)
draw_item_name($data_armors[@actor.armor3_id], 320 + 16, 352)
draw_item_name($data_armors[@actor.armor4_id], 320 + 16, 400)
end
end

复制代码

只能做到这里 {/gg}

帮助来自柳之一http://rpg.blue/web/htm/news836.htm
填充是用for循环画线

上面的三角形填充因为能力值的变化所以不规范
两个for循环却出现意外

并且建议如果可以的话就把所有的a[1][0]样的坐标
改为数字（大概坐标看不出来破绽的不过严格说是不对的）
a[0] = [r, h] #圆心       =
a[1] = [r / 2, 0.0]       =110 220
a[2] = [r * 3 / 2, 0.0] =210 220
a[3] = [r * 2, h]       =260 306
a[4] = [r * 3 / 2, h * 2]  =210 392
a[5] = [r / 2, h * 2]    =110 392
a[6] = [0.0, h]          =60  306
但是有一个好处改了之后卡的现象可能会好点{/gg}

多说一句：如果像我做的这样还不如不做
因为填充会卡配置低点的机器……
倒不如默认的看起来爽快{/gg}

亿万星辰 · 发表于 2008-10-23 17:57:58

多边形的填充算法可以用种子填充或者扫描线填充或者二者结合，但好像效率都不是很高

redant · 发表于 2008-10-23 18:03:56

亿万大哥这个C里有
floodfill(200,200,1);
/* 填充(点x，y, 边界色) */
的方法 rgss里有不过只能填充矩形么？

另外什么是种子填充？{/gg}

亿万星辰 · 发表于 2008-10-23 19:27:37

这个有意思，我要玩玩看……{/hx}

种子填充就是类似画笔里的那种，一个区域里给定一个点，然后这个区域就会被填充，不过往往这两种填充方法是结合使用的。

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